5x^2-57=0

Solution for 5x^2-57=0 equation:

5x^2-57=0

a = 5; b = 0; c = -57;
Δ = b2-4ac
Δ = 02-4·5·(-57)
Δ = 1140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1140}=\sqrt{4*285}=\sqrt{4}*\sqrt{285}=2\sqrt{285}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{285}}{2*5}=\frac{0-2\sqrt{285}}{10}
=-\frac{2\sqrt{285}}{10}
=-\frac{\sqrt{285}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{285}}{2*5}=\frac{0+2\sqrt{285}}{10}
=\frac{2\sqrt{285}}{10}
=\frac{\sqrt{285}}{5}
$